3x^2=70+x

Solution for 3x^2=70+x equation:

3x^2=70+x

We move all terms to the left:

3x^2-(70+x)=0

We add all the numbers together, and all the variables

3x^2-(x+70)=0

We get rid of parentheses

3x^2-x-70=0

We add all the numbers together, and all the variables

3x^2-1x-70=0

a = 3; b = -1; c = -70;
Δ = b2-4ac
Δ = -12-4·3·(-70)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-29}{2*3}=\frac{-28}{6}
=-4+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+29}{2*3}=\frac{30}{6}
=5
$